9c^2+21c+10=

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Solution for 9c^2+21c+10= equation:


Simplifying
9c2 + 21c + 10 = 0

Reorder the terms:
10 + 21c + 9c2 = 0

Solving
10 + 21c + 9c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5 + 3c)(2 + 3c) = 0

Subproblem 1

Set the factor '(5 + 3c)' equal to zero and attempt to solve: Simplifying 5 + 3c = 0 Solving 5 + 3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 3c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 3c = 0 + -5 3c = 0 + -5 Combine like terms: 0 + -5 = -5 3c = -5 Divide each side by '3'. c = -1.666666667 Simplifying c = -1.666666667

Subproblem 2

Set the factor '(2 + 3c)' equal to zero and attempt to solve: Simplifying 2 + 3c = 0 Solving 2 + 3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3c = 0 + -2 3c = 0 + -2 Combine like terms: 0 + -2 = -2 3c = -2 Divide each side by '3'. c = -0.6666666667 Simplifying c = -0.6666666667

Solution

c = {-1.666666667, -0.6666666667}

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